SSC GD Important Questions for Elementary Mathematics

The SSC GD Important Questions for Elementary Mathematics guides your success in the SSC GD exam forming the subject fundamental for the SSC GD 2025 examination. Successful candidates must learn basic mathematical principles including Ratio and Proportion fundamentals and Averages and Percentage concepts followed by advanced instruction in Algebra and Geometry and Trigonometry. This page showcases SSC GD Elementary Mathematics important questions together with expert advice and time-saving techniques to solve problems effectively. The resources offered here present SSC GD practice set for Maths to help you strengthen your basic skills while delivering expertise in Data Interpretation alongside Mensuration concepts so you can succeed in the upcoming SSC GD examination.

SSC GD Ratio and Proportion Important Questions 2025

Your success in scoring points on the upcoming SSC GD exam 2025 depends on your ability to master Ratio and Proportion topics. Real-life numerical problems that display relationships between quantities make up the content of this particular topic. Build speed and accuracy for Ratio and Proportion questions by practicing SSC GD important questions alongside learning time-saving answer strategies for maximum exam success.

Q1. What is the ratio of mean proportional between 4.8 and 10.8 and the third proportional to 0.4 and 2.4?

4.8 और 10.8 के बीच औसत आनुपातिक और 0.4 और 2.4 के तीसरे समानुपाती का अनुपात क्या है?

(1)    2:1
(2)    3:2
(3)    1:2
(4)    2:3

Explanation : (3) 

Mean proportional = √4.8 x 10.8 (a/M.P. = M.P./b implies that MP = √ab)
Mean proportional = 7.2
Third proportional = 2.4 x 2.4 / 0.4 (a/b = b/T.P. implies that T.P. = b2/a)
Third proportional = 14.4
Ratio of mean proportional to third proportional = 7.2/14.4 = 1:2
 

SSC GD Average Important Questions 2025

The SSC GD Average segment contains important mathematical questions that can produce high scores. The subject demands calculations between group averages combined with weighted and combined averages. Solving important SSC GD Average problems will help you enhance your accuracy and confidence for your upcoming 2025 exam.

Q2. The average of 12 numbers is 55.5. The average of first 4 numbers is 53.4 and that of the next four numbers is 54.6. The 10th number is greater than the 9th number by 3 but lesser than the 11th and 12th numbers by 2 and 3, respectively. What is the average of the 10th number and the 12th numbers?

12 संख्याओं का औसत 55.5 है। पहली चार संख्याओं का औसत 53.4 है और अगली चार संख्याओं का औसत 54.6 है। 10वीं संख्या 9वीं संख्या से 3 अधिक लेकिन 11वीं और 12वीं संख्या से क्रमशः 2 और 3 कम है।10वीं और 12वीं संख्या का औसत क्या है?

(1)    59.5
(2)    58
(3)    57.5
(4)    56

Explanation : (1) 

The average of first four numbers = 53.4
Sum of first four numbers = 53.4 * 4 = 213.6
The average of next four numbers = 54.6 

Sum of next four numbers = 54.6 * 4 = 218.4

Sum of the first eight digits = 213.6 + 218.4 = 432
The average of 12 (i.e. all) numbers = 55.5 

Sum of 12 (i.e. all) numbers = 55.5 * 12 = 666

Therefore, sum of the last four numbers = 666 – 432 = 234… (i)
Let the 10th number be = x, so 9th number = x-3, 11th number = x+2 and 12th number = x+3.
Sum of 9th, 10th, 11th and 12th numbers(i.e. last four numbers) = (x-3) + x + (x+2)+(x+3) = 4x +2…(ii)

From (i) and (ii)
4x + 2 = 234
4x = 232
x = 58

Average of 10th and 12th number = (2x+3)/2 = [(58 * 2) + 3] / 2 = 59.5

पहली चार संख्याओं का औसत = 53.4
पहली चार संख्याओं का योग = 53.4 * 4 = 213.6
अगली चार संख्याओं का औसत = 54.6
अगली चार संख्याओं का योग = 54.6 * 4 = 218.4
पहले आठ अंकों का योग = 213.6 + 218.4 = 432

12 (अर्थात सभी) संख्याओं का औसत = 55.5
12 (अर्थात सभी) संख्याओं का योग = 55.5 * 12 = 666

अत: अंतिम चार संख्याओं का योग = 666 – 432 = 234… (i)
मान लीजिए कि 10वीं संख्या = x है, इसलिए 9वीं संख्या = x-3, 11वीं संख्या = x+2 और 12वीं संख्या = x+3 है।

9वीं, 10वीं, 11वीं और 12वीं संख्याओं का योग (अर्थात अंतिम चार संख्याएं) 
= (x-3) + x + (x+2)+(x+3) = 4x +2…(ii)    

(i) और (ii) से
4x + 2 = 234
4x = 232
x = 58

10वीं और 12वीं संख्या का औसत = (2x+3)/2 = [(58 * 2) + 3]/2 = 59.5
 

SSC GD Number system Important Questions 2025

The Number System functions as fundamental content within SSC GD Mathematics 2025. Essential number system concepts appear in examination questions that focus on divisibility problems LCM and HCF computations and base conversion methods. Utilize Number System questions for SSC GD examinations to practice basics while raising your exam score data.

Q3. A farmer divides his herd of n cows among his four sons so that the first son gets one-half the herd, the second son gets one-fourth, the third son gets one-fifth and the fourth son gets 7 cows. The value of n is : 

(1)    80
(2)    100
(3)    140
(4)    180

Explanation : (3) Let there is ‘n’ cows

According to the question
n – (1/2)n – (1/4)n – (1/5)n = 7
(20n – 10n – 5n – 4n)/20 = 7
n = 140 

SSC GD Simplification Important Questions 2025

Candidates who want to succeed in SSC GD 2025 exams must demonstrate mastery of BODMAS rules paired with basic mathematical calculation skills. Working on practice Ratio and Proportion SSC GD questions can help you learn effective methods while decreasing your possibility of mistakes along with boosting your problem-solving rate.

Q4. The value of  is 

उपरोक्त का मान है

(1)    3 ½ 
(2)    1 ½ 
(3)    1 ¼ 
(4)    3 1/8 

Explanation : (2) Applying BODMAS rule

 

SSC GD Time and work Important Questions 2025

The revision of SSC GD 2025 heavily tests your abilities to reason logically and analyze situations through Time and Work questions. Learning effective approaches for work calculations manpower assessment and time rate relationships becomes possible through practice with important SSC GD Time and Work questions.

Q5. Five men can complete a work in 20 days. Ten women can complete the same work in 15 days. Two men and six women started working together. After 5 days, three women left the work and a new man joined the work. The group continued working together till the end of the work. In how many days will they be able to do the remaining work?

पांच आदमी एक काम को 20 दिनों में पूरा कर सकते हैं। दस महिलाएं उसी कार्य को 15 दिनों में पूरा कर सकती हैं। दो पुरुषों और छह महिलाओं ने एक साथ काम करना शुरू किया। 5 दिनों के बाद, तीन महिलाओं ने काम छोड़ दिया और एक नया आदमी काम में शामिल हो गया। समूह ने काम के अंत तक एक साथ काम करना जारी रखा। शेष कार्य को वे कितने दिनों में कर सकेंगे?

(1)    16 2/3 days (दिन)
(2)    18 1/3 days (दिन)
(3)    19 days (दिन)
(4)    14 days (दिन)

Explanation : (4) 

5M x 20 days = 10W x 15 days = Total work
M/W = 3/2
Total work = 5 x 3 x 20 = 10 x 2 x 15 = 300
Work completed by 2 men and  6 women in 5 days = (2x3 + 6x2)x5 = 18 x 5 = 90
Remaining work = 300 – 90 = 210
Time taken to complete the remaining work by 3 men and 3 women as 3 women have left and 1 men has joined the work
= 210 / (3 x 3 + 3 x 2) = 210 / 15 = 14 days

5M x 20 दिन = 10W x 15 दिन = कुल कार्य
M / W = 3/2
कुल कार्य = 5 x 3 x 20 = 10 x 2 x 15 = 300
2 पुरुषों और 6 महिलाओं द्वारा 5 दिनों में पूरा किया गया कार्य = (2x3 + 6x2)x5 = 18 x 5 = 90
शेष कार्य = 300 - 90 = 210
शेष कार्य को 3 पुरुषों और 3 महिलाओं द्वारा पूरा करने में लिया गया समय, क्योंकि 3 महिलाओं ने काम छोड़ दिया है और 1 पुरुष कार्य में शामिल हो गया है
= 210 / (3 x 3 + 3 x 2) = 210 / 15 = 14 दिन

SSC GD Time, speed and distance Important Questions 2025

Students must study Time Speed Distance principles because examiners conduct thorough examinations of this topic within the SSC GD exam 2025. This topic examines your skill at determining travel duration alongside mutual velocity between objects and calculating anterior-measured lengths. Strengthen your accuracy and learn time-saving methods through practice with critical questions from SSC GD Time, Speed, and Distance.

Q6. The speed of train A is 25 km/h more than the speed of train B. A takes 4 hours less time to travel a distance of 300 km than what train B takes to travel 250km. What is the speed (in km/h) of A?

ट्रेन A की गति ट्रेन B की गति से 25 किमी/घंटा अधिक है। A को ट्रेन B द्वारा 250 किमी की यात्रा करने में लगने वाले समय की तुलना में 300 किमी की दूरी तय करने में 4 घंटे कम समय लगता है। A की गति (किमी/घंटा में) क्या है?

(1)    60
(2)    50
(3)    65
(4)    55

Explanation : (2)

If we try to solve the question through the conventional way, the equations would become too complicated and take up much time.
The best approach for these kinds of questions is to try and solve the questions through option substitution.
If we take option (2), then 

Speed of A = 50 km/h
Speed of B = 25 km/h

Distance travelled by A= 300 km
Distance travelled by B = 250 km

Time taken by A = 300 / 50 = 6 hours
Time taken by B = 250 / 25 = 10 hours

Hence, A takes 4 hours less time to travel a distance of 300 km than what B takes to travel 250 km, which satisfies the condition of the question. Hence, (2) is correct.

यदि हम पारंपरिक तरीके से प्रश्न को हल करने का प्रयास करते हैं, तो समीकरण बहुत जटिल हो जाते हैं और इसमें अधिक समय लगता है।
इस प्रकार के प्रश्नों के लिए सबसे अच्छा तरीका विकल्प प्रतिस्थापन के माध्यम से प्रश्नों को हल करने का प्रयास करना है।

यदि हम विकल्प (2) लेते हैं, तो

A की गति = 50 किमी/घंटा
B की गति = 25 किमी/घंटा

A द्वारा तय की गई दूरी = 300 किमी
B द्वारा तय की गई दूरी = 250 किमी

A द्वारा लिया गया समय = 300/50 = 6 घंटे
B द्वारा लिया गया समय = 250/25 = 10 घंटे

अत: A, B द्वारा 250 किमी की दूरी तय करने में लगने वाले समय से 300 किमी की दूरी तय करने में 4 घंटे कम समय लेता है, जो प्रश्न की शर्त को पूरा करता है। अतः (2) सही है।

SSC GD Simple interest and compound interest Important Questions 2025

The SSC GD Math examination includes Simple Interest and Compound Interest sections which offer students excellent opportunities to earn top marks. Practical financial explanations and formula applications make up the core material tested in these topic areas. By solving important questions from SSC GD SI and CI you can build your confidence to master this vital part of the exam.

Q7. Out of Rs. 50,000 that a man has, he lends Rs. 8000 at 5 ½ % per annum simple interest and Rs. 24000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3680. The rate of interest per annum, at which the remaining money is lent, is

एक आदमी के पास 50,000 रुपये में से, वह 8000 रुपये 5 ½% प्रति वर्ष साधारण ब्याज पर और 24000 रुपये 6% प्रति वर्ष साधारण ब्याज पर उधार देता है। वह शेष धनराशि को एक निश्चित ब्याज दर पर उधार देता है ताकि उसे 3680 रुपये का कुल वार्षिक ब्याज प्राप्त हो। प्रति वर्ष ब्याज की दर, जिस पर शेष धन उधार दिया जाता है, है

(1)    5%
(2)    7%
(3)    10%
(4)    12%

Explanation : (3) Remaining amount = 50,000 – (8000 + 24000) = Rs. 18000
Let rate of interest be = R%

According to the question,
[(8000/100)x(11/2)x1] + [(24000/100)x(6)x1] + [(18000/100)xR = 3680
=(44000/100) + (144000/100) + (18000R/100) = 3680
18000R/100 = 3680 – 1880
180R = 1800
R = 10%
Hence, required rate = 10%

शेष राशि = 50,000 – (8000 + 24000) = 18000 रुपये
माना ब्याज दर = R%

प्रश्न के अनुसार,
[(8000/100)x(11/2)x1] + [(24000/100)x(6)x1] + [(18000/100)xR = 3680
=(44000/100) + (144000/100) + (18000R/100) = 3680
18000R/100 = 3680 - 1880
180R = 1800
R = 10%

अत: अभीष्ट दर = 10%

SSC GD Profit, loss and discount Important Questions 2025

Profit Loss and Discount questions have a major placement in the SSC GD exam 2025. Master essential concepts between cost price and selling price along with discount percentage knowledge. Practicing SSC GD Profit Loss and Discount important questions teaches you faster calculation methods which leads to better exam score results, as suggested by our experts in Tricks for Ratio and Proportion in exams. 

Q8. By how much above the cost price should an article be marked up for sale so that after allowing two successive discounts of 20% and 6.25% on it, a net gain of 20% is made on the cost price?

एक वस्तु को बिक्री के लिए लागत मूल्य से कितना अधिक अंकित किया जाना चाहिए ताकि उस पर 20% और 6.25% की लगातार दो छूट देने के बाद, लागत मूल्य पर 20% का शुद्ध लाभ हो?

(1)    66 2/3 %
(2)    46 ¼ %
(3)    50%
(4)    60%

Explanation : (4) 

Profit / लाभ = 20%            Discount / बट्टा = 20% and 6.25%

By using the concept of multiplying factor, we get
C.P = 1, S.P. = 1.2, Discount 1 = 0.8 and Discount 2 = 0.9375

Therefore, M.P. = S.P./D1 x D2 
1.2 / 0.8 x 0.9375 = 1.6

Therefore, the article needs to be marked up 60% above its C.P.

गुणन कारक की अवधारणा का उपयोग करके, हम प्राप्त करते हैं
सीपी = 1, एसपी = 1.2, बट्टा 1 = 0.8 और बट्टा 2 = 0.9375

इसलिए, एम.पी. = एसपी/डी1 x डी2
1.2 / 0.8 x 0.9375 = 1.6

इसलिए, वस्तु को उसके सी.पी. से 60% ऊपर अंकित करने की आवश्यकता है।

Q9. A shopkeeper bought 20 kg of sugar at Rs. 45 per kg, 25 kg of sugar at Rs. 50 per kg and 35 kg of sugar at Rs. 40 per kg. he spent a sum of Rs. 450 on transportation and other expenses. He mixed all the three types of sugar and sold all the stock at Rs. 52.50 per kg. his profit percent in the entire transaction is

एक दुकानदार ने 20 किलो चीनी 45 रुपये प्रति किलो, 25 किलो चीनी 50 रुपये प्रति किलो और 35 किलो चीनी 40 रुपये प्रति किलो की दर से खरीदी। उन्होंने परिवहन और अन्य खर्चों पर 450 रुपये की राशि खर्च की। उसने तीनों प्रकार की चीनी मिला दी और सारा स्टॉक 52.50 रुपये प्रति किलो के भाव से बेच दिया। पूरे लेनदेन में उसका लाभ प्रतिशत है

(1)    6.5
(2)    5
(3)    7.25
(4)    4.25

Explanation : (2) Total cost price of the whole batch
=20 x 45 + 25 x 50 + 35 + 40 + 450 = 900 + 1250 + 1400 + 450 

Total cost price = Rs. 4000
Weight of total batch = 80 kg
Selling price of the whole batch = 52.50 x 80 = Rs. 4200
Profit = Rs. 4200 – 4000 = Rs. 200
Profit % = (200/4000)x100 = 5%

पूरे बैच का कुल लागत मूल्य
=20 x 45 + 25 x 50 + 35 + 40 + 450 = 900 + 1250 + 1400 + 450 

कुल लागत मूल्य = रु. 4000
कुल बैच का वजन = 80 किग्रा
पूरे बैच का विक्रय मूल्य = 52.50 x 80 = रु. 4200

लाभ = रु. 4200 - 4000 = रु. 200
लाभ% = (200/4000)x100 = 5%
 

SSC GD Geometry Important Questions 2025

The understanding of shapes angles and theorems constitutes a core part of Ratio problems for SSC GD while challenging candidates. The major geometrical topics include triangles, circles and quadrilaterals. Studying important questions from SSC GD Geometry will help build your problem-solving ability so you can handle this section with confidence.

Q10. In triangle ABC, AM is perpendicular to BC and AN is the bisector of angle A. What is the measure of angle MAN, if angle B = 55◦ and angle C = 35◦?

त्रिभुज ABC में, AM BC पर लंबवत है और AN कोण A का समद्विभाजक है। कोण MAN का माप क्या है, यदि कोण B = 55◦ और कोण C = 35◦ है?

(1)    10◦
(2)    12◦
(3)    15◦
(4)    5◦

Explanation : (1) In such a situation as is given in the question, a direct relation is there which needs to be remembered in order to solve the question quickly. This is
Angle MAN = ½ (angle B – angle C)
Applying it here, we get
Angle MAN = ½ (55◦ - 35◦) = 10◦

ऐसी स्थिति में जैसा कि प्रश्न में दिया गया है, एक सीधा संबंध है जिसे याद रखने की आवश्यकता है ताकि प्रश्न को जल्दी हल किया जा सके। ये है
कोण MAN = ½ (कोण B - कोण C)
इसे यहाँ लागू करने पर, हमें प्राप्त होता है
कोण MAN = ½ (55◦ - 35◦) = 10◦

Q11. In triangle ABC, AD is the bisector of angle A meeting BC at D. If AC = 21 cm, BC = 11cm and the length of BD is 3 cm less than DC, then the length (in cm) of side AB is
त्रिभुज ABC में, AD कोण A का समद्विभाजक है जो BC को D पर मिलता है। यदि AC = 21 सेमी, BC = 11 सेमी और BD की लंबाई DC से 3 सेमी कम है, तो भुजा AB की लंबाई (सेमी में) है

(1)    18
(2)    10
(3)    12
(4)    15

Explanation : (3) 
Using the interior angle bisector theorem, we have
आंतरिक कोण समद्विभाजक प्रमेय का उपयोग करते हुए, हमारे पास है

AB/AC = BD/DC

Here, AC = 21 cm, BC = 11 cm
As BD is 3cm less than CD, so BD = 4 cm and CD = 7 cm
Hence, AB / 21 = 4/7
Therefore, AB = 12cm 

यहाँ, AC = 21 सेमी, BC = 11 सेमी
चूँकि BD, CD से 3 सेमी कम है, इसलिए BD = 4 सेमी और CD = 7 सेमी
अत: AB / 21 = 4/7
इसलिए, AB = 12cm
 

SSC GD Mensuration Important Questions 2025

During the SSC GD exam 2025 you need to focus deeply on Mensuration since it encompasses the calculation of areas and volumes for two-dimensional and three-dimensional geometric shapes. You can excel in the circles, cones, and spheres-meaning different organizations by solving essential SSC GD Mensuration practice questions that reinforce formulas alongside effective problem-solving techniques.

Q 12. The area of a field in the shape of a triangle with each side x metres is equal to the area of another triangular field having sides 50m, 70m and 80m. The value of x is closest to 

एक त्रिभुज के आकार के एक खेत का क्षेत्रफल जिसकी प्रत्येक भुजा x मीटर है, एक अन्य त्रिभुजाकार खेत के क्षेत्रफल के बराबर है, जिसकी भुजाएँ 50m, 70m और 80m हैं। x का मान के निकटतम है

(1)    65.5
(2)    63.2
(3)    62.4
(4)    61.8

Explanation : (2) Area of an equilateral triangle = (√3/4)(side)2…(i)

Area of scalene triangle = √(s)(s – a)(s – b)(s – c), where s = semi perimeter, a, b and c are sides of the triangle.
Here a = 50 m, b = 70m and c = 80 m.
Semi perimeter = (50 + 70 + 80)/2 = 100
Area of the scalene triangle = √(100)(100 – 50)(100 – 70)(100 – 80) 

= √100 x 50 x 30 x 20 = 1732 m2…(ii)

From (i) and (ii)
(√3/4)(side)2 = 1732
(side)2 = 1732 x 4 / √3
Side = 63.2 (approx.)    

एक समबाहु त्रिभुज का क्षेत्रफल = (√3/4)(भुजा)2…(i)    

विषमकोण त्रिभुज का क्षेत्रफल = √(s)(s – a)(s – b)(s – c), जहाँ s = अर्ध परिमाप, a, b और c त्रिभुज की भुजाएँ हैं।
यहाँ a = 50 m, b = 70m और c = 80 m।
अर्ध परिमाप = (50 + 70 + 80)/2 = 100
विषमकोण त्रिभुज का क्षेत्रफल = √(100)(100 – 50)(100 – 70)(100 – 80)

= 100 x 50 x 30 x 20 = 1732 मी2…(ii)    

(i) और (ii) से
(√3/4)(भुजा)2 = 1732
(भुजा)2 = 1732 x 4 / 3
भुजा = 63.2 (लगभग)

Q13. A sector is cutout from a circle of diameter 42 cm. If the angle of the sector is 150◦, then its area (in cm2) is 
(Take π = 22/7) 

एक त्रिज्यखंड को 42 सेमी व्यास वाले वृत्त से काटा जाता है। यदि त्रिज्यखंड का कोण 150◦ है, तो इसका क्षेत्रफल (सेमी2 में) है

(1)    564
(2)    574
(3)    580.6
(4)    577.5

Explanation: (4)

Area of the sector = (Sector angle / 360◦) x πr2

=(150◦/ 360◦) x (22/7) x (21)2
= 577.5 cm2

त्रिज्यखंड का क्षेत्रफल = (सेक्टर कोण / 360◦) x πr2

=(150◦/ 360◦) x (22/7) x (21)2
= 577.5 सेमी2

SSC GD Trigonometry Important Questions 2025

SSC GD Mathematics contains trigonometry as a difficult part that students can make high scores with. Topics under examination focus on angles together with values associated with sine, cosine, and tangent. Study the essential SSC GD Trigonometry problems since they help make calculations easier which leads to higher success in this crucial material.

Q14. For 0◦ < A < 90◦,
(1/cos A) + [1 / (tan A – sec A)] is equal to

0◦ < A <90◦ के लिए,
उपरोक्त बराबर है

(1) Tan A
(2) Sec A
(3) Tan A
(4) Sec A

Explanation : (3) Taking A = 45◦

(1/cos A) + [1 / (tan A – sec A)] = (1/1/√2) + [1 / (1 – √2)]
=[√2 (1 - √2) + 1] / (1 - √2) = (√2 – 2 + 1) / 1 - √2 = (√2 – 1) / - (√2 – 1)
= -1

Putting A = 45◦ in options
In option (3) we get 
(- tan A) = - tan 45◦ = -1 
 

SSC GD Percentage Important Questions 2025

Percentage problems present simple solutions though you need a firm foundation to solve them. The evaluation consists of questions that compare data alongside calculations of profits and discount applications. The solution to mastering SSC GD Percentage questions lies in important questions that can enhance both your accuracy and efficiency at solving these critical concepts.

Q15. A is 20% less than B and C is 30% more than D. If D is 25% less than A, then which of the following is true?

A, B से 20% कम है और C, D से 30% अधिक है। यदि D, A से 25% कम है, तो निम्न में से कौन सा सत्य है? 

(1)    B = 0.39 C
(2)    C = 0.78 B
(3)    B = 0.78 C
(4)    C = 0.39 B

Explanation: (2)

A : B = 4 : 5, C : D = 13 : 10 

   and D : A = 3 : 4

Therefore, C : D : A = 39 : 30 : 40 and A : B = 40 : 50
So, C/B = 39/50
C = 0.78 B
 

SSC GD Algebra Important Questions 2025

In the SSC GD exam, students need to master algebra concepts as they must execute problem-solving methods for equations and inequalities. Students who want to understand polynomials, linear equations, and factorization methods should complete important problems from SSC GD Algebra.

Q16. If , then 

यदि , then 

(1)    4
(2)    2
(3)    1
(4)    0

Explanation : (2) 

Using a3 – b3 = (a – b)(a2 + ab + b2)
x3 - 2√2y3 = (x - √2y)(x2 + √2xy + 2y2)
(x3 - 2√2y3)/ (x - √2y) = (x2 + √2xy + 2y2) = Ax2 + Bxy + Cy2

On comparison, we find that A = 1, B = √2 and C = 2

So, the value of expression asked = (2*1 + 4√2*√2 + - 4*2) = 2 + 8 – 8 = 2

तुलना करने पर, हम पाते हैं कि A = 1, B = 2 और C = 2

अतः पूछे गए व्यंजक का मान = (2*1 + 4√2*√2 + - 4*2) = 2 + 8 - 8 = 2
 

SSC GD Data Interpretation Important Questions 2025

Analytical reasoning together with numerical understanding is demonstrated through Data Interpretation questions in the SSC GD examination. Practice SSC GD Data Interpretation important questions from pie charts, bar graphs, and tables to develop both speed and accuracy in this scoring portion.

Q17. – Q20. The following pie chart shows the preference of musical instruments of 60,000 people surveyed over whole of India. Examine the chart and answer the questions.

निम्नलिखित पाई चार्ट पूरे भारत में सर्वेक्षण किए गए 60,000 लोगों के संगीत वाद्ययंत्रों की पसंद को दर्शाता है। चार्ट की जांच करें और प्रश्नों के उत्तर दें।

Q17. If 2100 people be less from the number of people who prefer Flute, the percentage of people who prefer flute would have been 

यदि 2100 लोग बांसुरी पसंद करने वालों की संख्या से कम होते, तो बांसुरी पसंद करने वालों का प्रतिशत होता
(1)    9.5%
(2)    6.5%
(3)    7.5%
(4)    8.5%

Explanation : (3)People who prefer flute = (11/100)x60000 = 6600

New number of people who prefer flute = 6600 – 2100 = 4500
New % = (4500/60000)x100 – 45/6 = 7.5%

बांसुरी पसंद करने वाले लोग = (11/100)x60000 = 6600

बांसुरी पसंद करने वालों की नई संख्या = 6600 – 2100 = 4500

नया% = (4500/60000)x100 - 45/6 = 7.5%

Q18. The total number of people who prefer either sarod or guitar, is greater than the total number of people who prefer either violin or sitar by

सरोद या गिटार पसंद करने वाले लोगों की कुल संख्या, वायलिन या सितार पसंद करने वालों की कुल संख्या से अधिक है

(1)    1200
(2)    1600
(3)    1100
(4)    1400

Explanation : (1)Percentage of people who prefer either sarod or guitar 
= 14% + 22% = 36%

Percentage of people who prefer either violin or sitar 
= 20% + 14% = 34%

Difference of percentage = 36% - 34% = 2%

Required answer = (2/100)x60000 = 1200

सरोद या गिटार पसंद करने वाले लोगों का प्रतिशत
= 14% + 22% = 36%

वायलिन या सितार पसंद करने वाले लोगों का प्रतिशत
= 20% + 14% = 34%
प्रतिशत का अंतर = 36% - 34% 

वांछित उत्तर = (2/100)x60000 = 1200

Q19. The number of people who prefer the musical instrument Sarod is

संगीत वाद्ययंत्र सरोद को पसंद करने वालों की संख्या है

(1)    7400
(2)    8400
(3)    6400
(4)    8600

Explanation : (2)60000 x (14/100) = 8400 

Q20. If 16 2/3% of the people who prefer piano, would go with the people who prefer flute, the percentage of people who prefer flute would have been

यदि 16 2/3% लोग जो पियानो पसंद करते हैं, बांसुरी पसंद करने वाले लोगों के साथ जाएंगे, तो बांसुरी पसंद करने वालों का प्रतिशत होगा

(1)    13.5
(2)    14.5
(3)    15.5
(4)    12.5

Explanation : (4)People who prefer piano = (9/100)x60000 = 5400

Now 16 2/3 % of 5400 = (1/6)x5400 = 900

People who prefer flute = (11/100)x60000 = 6600

New number of people who prefer flute = 900 + 6600 = 7500

Required percentage = (7500/60000)x100 = 75/6 = = 12.5%

पियानो पसंद करने वाले लोग = (9/100)x60000 = 5400

अब 5400 का 16 2/3% = (1/6)x5400 = 900

बांसुरी पसंद करने वाले लोग = (11/100)x60000 = 6600

बांसुरी पसंद करने वालों की नई संख्या = 900 + 6600 = 7500

वांछित प्रतिशत = (7500/60000)x100 = 75/6 = = 12.5%

Conclusion 

The SSC GD 2025 exam success depends heavily on your ability to understand Elementary Mathematics. You can improve both your mathematical problem-solving ability and accuracy level through the regular practice of essential questions in Ratio and Proportion, Averages, Geometry, and Data Interpretation topics. Previous year questions should serve as practice material alongside concept learning and shortcut technique acquisition to develop your confidence. Practice sets performed at regular intervals will help you develop exam habits as well as manage your time more effectively. Through proper Math preparation and dedication, you can achieve top results in the SSC GD exam. Launch your study effort today because staying ahead matters.

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